Search alternatives:
ng decrease » nn decrease (Expand Search), _ decrease (Expand Search), we decrease (Expand Search)
e decrease » _ decrease (Expand Search), _ decreased (Expand Search), _ decreases (Expand Search)
a decrease » _ decrease (Expand Search), _ decreased (Expand Search), _ decreases (Expand Search)
100 ng » 100 mg (Expand Search), 100 nm (Expand Search), 100 ns (Expand Search)
ng decrease » nn decrease (Expand Search), _ decrease (Expand Search), we decrease (Expand Search)
e decrease » _ decrease (Expand Search), _ decreased (Expand Search), _ decreases (Expand Search)
a decrease » _ decrease (Expand Search), _ decreased (Expand Search), _ decreases (Expand Search)
100 ng » 100 mg (Expand Search), 100 nm (Expand Search), 100 ns (Expand Search)
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Regenerating axons are increased by ATRA and decreased by clodronate.
Published 2021“…<p>(A—E) Confocal images of immunohistochemical staining of growing axons with anti-GAP43 antibody (green), in longitudinal sections of the optic nerve at 2 weeks after axotomy. …”
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Osr1 heterozygous mice experienced decreased bile acid synthesis in the liver.
Published 2022“…<p>(A). Osr1 male mice had a decreased trend of hepatic bile acid compared to WT mice. …”
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The decrease or inhibition of Hsp90 induced REST degradation.
Published 2019“…<p>(A) Effect of Hsp90α ASO on cell viability. Differentiated SH-SY5Y cells were transfected with different concentrations of Hsp90α ASO. …”
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Repetitive stress induces a decrease in sound-evoked activity.
Published 2025“…(d) Noise-evoked activity rates at different noise intensities for chronically tracked PV cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 31 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 49.6, <i>p</i> = 2.6 × 10<sup>−12</sup>, condition: intensity interaction F = 1.94, <i>p</i> = 0.02, nested ANOVA (mouse nested within session), F = 56.5, <i>p</i> = 8.8 × 10<sup>−14</sup>, condition: intensity interaction F = 3.5, <i>p</i> = 3.5 × 10<sup>−05</sup>). …”
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