Showing 161 - 180 results of 44,288 for search '(((( 5 we decrease ) OR ( 50 ((a decrease) OR (mean decrease)) ))) OR ( 2 step decrease ))', query time: 0.98s Refine Results
  1. 161

    S1 File - by Yonghui Zhang (279832)

    Published 2024
    “…Root means square error (RMSE) (mean absolute error (MAE), coefficient of determination (R<sup>2</sup>), and Nash Sutcliffe model efficiency (NSE)) are 15.50 (14.63, 0.96, 0.42), 4.76 (3.92, 0.97, 0.95), 4.69 (3.72, 0.98, 0.95), 3.91 (3.40, 0.99, 0.96) and 12.54 (11.67, 0.95, 0.60), 5.07 (4.61, 0.98, 0.93), 4.97 (4.28, 0.97, 0.94), 4.58 (4.02, 0.98, 0.95) for using one, two, three, and four observed phenological stages in the CSPs estimation. …”
  2. 162

    Detailed information on field experiments. by Yonghui Zhang (279832)

    Published 2024
    “…Root means square error (RMSE) (mean absolute error (MAE), coefficient of determination (R<sup>2</sup>), and Nash Sutcliffe model efficiency (NSE)) are 15.50 (14.63, 0.96, 0.42), 4.76 (3.92, 0.97, 0.95), 4.69 (3.72, 0.98, 0.95), 3.91 (3.40, 0.99, 0.96) and 12.54 (11.67, 0.95, 0.60), 5.07 (4.61, 0.98, 0.93), 4.97 (4.28, 0.97, 0.94), 4.58 (4.02, 0.98, 0.95) for using one, two, three, and four observed phenological stages in the CSPs estimation. …”
  3. 163

    List of symbols used in this study. by Yonghui Zhang (279832)

    Published 2024
    “…Root means square error (RMSE) (mean absolute error (MAE), coefficient of determination (R<sup>2</sup>), and Nash Sutcliffe model efficiency (NSE)) are 15.50 (14.63, 0.96, 0.42), 4.76 (3.92, 0.97, 0.95), 4.69 (3.72, 0.98, 0.95), 3.91 (3.40, 0.99, 0.96) and 12.54 (11.67, 0.95, 0.60), 5.07 (4.61, 0.98, 0.93), 4.97 (4.28, 0.97, 0.94), 4.58 (4.02, 0.98, 0.95) for using one, two, three, and four observed phenological stages in the CSPs estimation. …”
  4. 164

    Data sources for calibration and evaluation. by Yonghui Zhang (279832)

    Published 2024
    “…Root means square error (RMSE) (mean absolute error (MAE), coefficient of determination (R<sup>2</sup>), and Nash Sutcliffe model efficiency (NSE)) are 15.50 (14.63, 0.96, 0.42), 4.76 (3.92, 0.97, 0.95), 4.69 (3.72, 0.98, 0.95), 3.91 (3.40, 0.99, 0.96) and 12.54 (11.67, 0.95, 0.60), 5.07 (4.61, 0.98, 0.93), 4.97 (4.28, 0.97, 0.94), 4.58 (4.02, 0.98, 0.95) for using one, two, three, and four observed phenological stages in the CSPs estimation. …”
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    Numbers of all fractures occurring in men, arranged in order of decreasing mean age, and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age. by Camilla Bergh (9904522)

    Published 2020
    “…<p>Numbers of all fractures occurring in men, arranged in order of decreasing mean age, and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age.…”
  8. 168

    Numbers of all fractures occurring in women, arranged in order of decreasing mean age, and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age. by Camilla Bergh (9904522)

    Published 2020
    “…<p>Numbers of all fractures occurring in women, arranged in order of decreasing mean age, and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age.…”
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    Advancing the science of NOWS research. by Sarah E. Maylott (14560785)

    Published 2024
    “…<div><p>Every 15 minutes in the US, an infant exposed to opioids is born. Approximately 50% of these newborns will develop Neonatal Opioid Withdrawal Syndrome (NOWS) within 5 days of birth. …”
  13. 173

    Protocol measures. by Sarah E. Maylott (14560785)

    Published 2024
    “…<div><p>Every 15 minutes in the US, an infant exposed to opioids is born. Approximately 50% of these newborns will develop Neonatal Opioid Withdrawal Syndrome (NOWS) within 5 days of birth. …”
  14. 174

    Cry variables. by Sarah E. Maylott (14560785)

    Published 2024
    “…<div><p>Every 15 minutes in the US, an infant exposed to opioids is born. Approximately 50% of these newborns will develop Neonatal Opioid Withdrawal Syndrome (NOWS) within 5 days of birth. …”
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