Showing 1 - 20 results of 35,358 for search '(((( 50 _ decrease ) OR ( 50 ((mean decrease) OR (_ decrease)) ))) OR ( 5 w decrease ))*', query time: 0.85s Refine Results
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    Decreased cell stiffness after dissociation of intercellular adhesion. by Kristina Seiffert-Sinha (627059)

    Published 2014
    “…In parallel, AFM-guided cell stiffness measurements were obtained by AFM nanomechanical measurement of 50 different cells under each of the conditions described above (<b>D</b>); Each bar represents the average and standard error of the mean (SEM) of repeated measurements for each condition. …”
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    Repetitive stress induces a decrease in sound-evoked activity. by Ghattas Bisharat (20706928)

    Published 2025
    “…<p>(a) Left: noise-evoked activity rates at different noise intensities for chronically tracked PPys cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 285 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 185.6, <i>p</i> = 4.8 × 10<sup>−42</sup>, condition: intensity interaction F = 10.37, <i>p</i> = 9.3 × 10<sup>−21</sup>, nested ANOVA (mouse nested within session), condition F = 174, <i>p</i> = 1.5 × 10<sup>−39</sup>, condition: intensity interaction F = 12.7, <i>p</i> = 2 × 10<sup>−26</sup>, post hoc for each level baseline versus repetitive stress <i>p</i> < 0.01 for all levels above 50 dB, all Bonferroni corrected). …”
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    Numbers of all fractures, arranged in order of decreasing mean age and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age. by Camilla Bergh (9904522)

    Published 2020
    “…<p>Numbers of all fractures, arranged in order of decreasing mean age and with proportion of each of the fracture types in patients over 50, 65, and 75 years of age.…”
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    Mean change in incidence and diagnoses if testing rates decrease. by Richard T. Gray (282417)

    Published 2013
    “…<p>Change in incidence (A) and diagnoses (B) if testing rates decrease by 30% and 50% relative to the current testing rate.…”
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