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values decrease » values increased (Expand Search), largest decrease (Expand Search)
cases increased » rate increased (Expand Search), levels increased (Expand Search)
c largest » _ largest (Expand Search), c large (Expand Search)
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Image 1_Exploration of the diagnostic and prognostic roles of decreased autoantibodies in lung cancer.tif
Published 2025“…</p>Results<p>In total, 15 types of decreased autoantibodies were identified, and 6 of them were constructed into a predictive model for early lung cancer, reaching a sensitivity of 76.19% and a specificity of 55.74%. …”
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TITAN thresholds and percentile estimates for benthic macroinvertebrate and diatom communities deemed to be sensitive decreasers or tolerant increasers. The thresholds represent the largest fsum <i>z</i> value in the main data analysis run (i.e., the median), whereas the 5<sup>th</sup> and 95<sup>th</sup> percentile change points are determined from 500 bootstrap replicate runs. Sensitive taxa change points derived from decreaser sum <i>z</i>- relative to increasing impervious cover (I.C.; %), specific conductivity (SpCond; μS cm<sup>-1</sup>), total nitrogen (TN; μg L<sup>-1</sup>), and total phosphorus (TP; μg L<sup>-1</sup>)....
Published 2025“…Sensitive taxa change points derived from decreaser sum <i>z</i>- relative to increasing impervious cover (I.C.; %), specific conductivity (SpCond; μS cm<sup>-1</sup>), total nitrogen (TN; μg L<sup>-1</sup>), and total phosphorus (TP; μg L<sup>-1</sup>). …”
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Drug-induced decrease of cell anisotropy reduces pattern fidelity.
Published 2022“…<b>(B)</b> Quantifications of primordia spacing variability on phalloïdin-stained control flat skins (explant; triangles) and LatA-treated cultured explants (+LatA; squares) of Japanese quail embryos showed that LatA treatment caused a significant decrease in pattern fidelity at condensation stage (explants, <i>n</i> = 9; +LatA, <i>n</i> = 9; unpaired 2-tailed <i>t</i> test; <i>p</i> = 0.0233) and differentiation stage (explants, <i>n</i> = 8; +LatA, <i>n</i> = 9; <i>p</i> = 0.002). …”
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