Showing 601 - 620 results of 232,945 for search '(( 2 we decrease ) OR ( 10 ((((ng decrease) OR (a decrease))) OR (mean decrease)) ))', query time: 1.73s Refine Results
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    ACE2 Is Augmented in Dystrophic Skeletal Muscle and Plays a Role in Decreasing Associated Fibrosis by Cecilia Riquelme (546116)

    Published 2014
    “…<div><p>Duchenne muscular dystrophy (DMD) is the most common inherited neuromuscular disease and is characterized by absence of the cytoskeletal protein dystrophin, muscle wasting, and fibrosis. We previously demonstrated that systemic infusion or oral administration of angiotensin-(1-7) (Ang-(1-7)), a peptide with opposing effects to angiotensin II, normalized skeletal muscle architecture, decreased local fibrosis, and improved muscle function in <i>mdx</i> mice, a dystrophic model for DMD. …”
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    Effect of freeze-thaw cycling on grain size of biochar - Fig 2 by Zuolin Liu (633898)

    Published 2018
    “…Numerical data for individual samples are presented in <a href="http://www.plosone.org/article/info:doi/10.1371/journal.pone.0191246#pone.0191246.s002" target="_blank">S2 Table</a>.…”
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    Rdh10a deficient embryos have decreased expression of RA signaling responsive genes. by Enrico D’Aniello (798447)

    Published 2015
    “…<p>(A-F) ISH for <i>cyp26a1</i>, <i>hoxb5b</i>, <i>and dhrs3a</i> expression in control sibling and Rdh10a deficient embryos. …”
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    Repetitive stress induces a decrease in sound-evoked activity. by Ghattas Bisharat (20706928)

    Published 2025
    “…(d) Noise-evoked activity rates at different noise intensities for chronically tracked PV cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 31 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 49.6, <i>p</i> = 2.6 × 10<sup>−12</sup>, condition: intensity interaction F = 1.94, <i>p</i> = 0.02, nested ANOVA (mouse nested within session), F = 56.5, <i>p</i> = 8.8 × 10<sup>−14</sup>, condition: intensity interaction F = 3.5, <i>p</i> = 3.5 × 10<sup>−05</sup>). …”
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