Showing 40,301 - 40,320 results of 60,795 for search '(( 50 ((026 decrease) OR (a decrease)) ) OR ( 5 ((nn decrease) OR (we decrease)) ))', query time: 1.26s Refine Results
  1. 40301
  2. 40302
  3. 40303
  4. 40304

    Cell viability. by Beatrice Bachmeier (219725)

    Published 2011
    “…<p>A) Different concentrations of artesunate reduce cell viability measured by MTT assay up to approximately 40% (50 µM) after 24 h in MDA-MB-231 cells (right panel), which was statistically significant (* <i>P</i><0.05; ** <i>P</i><0.01; *** <i>P</i><0.001; one way Anova with Bonferroni's post test). …”
  5. 40305
  6. 40306
  7. 40307

    Characterization of Nt5e activity on <i>S. sanguinis</i> 133-79 whole cells. by Jingyuan Fan (159998)

    Published 2012
    “…The curve was fitted to a sigmoidal inhibitory dose-response curve and the inhibitory concentration 50% (IC<sub>50</sub>) value derived from the curve fit was shown. …”
  8. 40308
  9. 40309
  10. 40310

    Drying kinetics and thermodynamic properties of bitter melon (Momordica charantia L.) leaves by Daniel P. da Silva (8591118)

    Published 2021
    “…<div><p>ABSTRACT Bitter melon (Momordica charantia L.) is a versatile plant that can be consumed as a food and has therapeutic applications. …”
  11. 40311
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  13. 40313
  14. 40314
  15. 40315
  16. 40316

    Viable <i>P. gingivalis</i> cleaves and prevents IL-2 accumulation. by Hazem Khalaf (308041)

    Published 2013
    “…<p><b>A</b>- Jurkat T-cells (10<sup>6</sup> cells/ml) were stimulated with 50 ng/ml PMA and 1 µg/ml Calcium ionophore for 24 h followed by exposure to viable <i>P. gingivalis</i> (Viable Pg, 10<sup>8</sup> CFU/ml, MOI:100) for the indicated times. …”
  17. 40317
  18. 40318
  19. 40319
  20. 40320

    Distance diffusion and shifts in FRET transfer efficiency. by Bram Wallace (4036730)

    Published 2017
    “…In the inset, we show the shift as a relative percentage given by <b>% shift</b> = |<i>E</i><sub>obs</sub> − <i>E</i><sub>0</sub>|/<i>E</i><sub>0</sub> with reference efficiency <i>E</i><sub>0</sub> = 0.5.…”