Showing 1 - 20 results of 37,837 for search '(( 50 ((ms decrease) OR (nn decrease)) ) OR ((( 50 _ decrease ) OR ( _ mean decrease ))))', query time: 1.27s Refine Results
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    Variable importance plot (mean decrease accuracy and mean decrease Gini). by Fernando Martinez-Taboada (8655132)

    Published 2020
    “…The higher the value of mean decrease accuracy or mean decrease Gini score, the higher the importance of the variable in the model.…”
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    Comparison of mean differences in temperature decreases. by Hans-Jörg Gillmann (8460585)

    Published 2022
    “…<p>Patients are grouped according to receiving either dipyrone (blue; n = 341) or acetaminophen (red; n = 71) versus patients receiving no antipyretic treatment (n = 315). Graphs display mean differences in temperature decreases between each two comparators (no medication versus dipyrone, no medication versus acetaminophen and dipyrone versus acetaminophen) with their respective 95% confidence intervals. …”
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    Repetitive stress induces a decrease in sound-evoked activity. by Ghattas Bisharat (20706928)

    Published 2025
    “…<p>(a) Left: noise-evoked activity rates at different noise intensities for chronically tracked PPys cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 285 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 185.6, <i>p</i> = 4.8 × 10<sup>−42</sup>, condition: intensity interaction F = 10.37, <i>p</i> = 9.3 × 10<sup>−21</sup>, nested ANOVA (mouse nested within session), condition F = 174, <i>p</i> = 1.5 × 10<sup>−39</sup>, condition: intensity interaction F = 12.7, <i>p</i> = 2 × 10<sup>−26</sup>, post hoc for each level baseline versus repetitive stress <i>p</i> < 0.01 for all levels above 50 dB, all Bonferroni corrected). …”
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    SLE decreases risk for hormonal cancers. by Deborah K. Johnson (10001156)

    Published 2021
    “…(b) Prostate cancer incidence in male SLE cohort is significantly decreased by SLE status (OR 0.23, 95% CI 0.089, 0.50, p = 0.0053).…”
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