Showing 1 - 20 results of 72,535 for search '(( 50 ((na decrease) OR (_ decrease)) ) OR ((( 5 c decrease ) OR ( 5 point decrease ))))*', query time: 1.35s Refine Results
  1. 1

    mGluR5 receptor decreased glycinergic currents. by Zi-Yang Zhang (4988555)

    Published 2019
    “…The original traces were taken at the time points indicated by the numbers 1–3. (<b>C</b>) The inhibitory effect of DHPG on GlyR-IPSCs was blocked by MPEP (92.4 ± 4.4% of baseline at 15–20 min post-DHPG, <i>t</i>[5] = 1.573, <i>p</i> = 0.177) but not by CPCCOEt (53.5 ± 3.7% of baseline at 15–20 min post-DHPG, <i>t</i>[5] = 14.343, <i>p</i> < 0.001). …”
  2. 2
  3. 3
  4. 4

    Downregulation of DOM decreases the abundance of PER and TIM. by Zhenxing Liu (399809)

    Published 2019
    “…Downregulation of DOM decreased PER levels at CT1-5 and CT17-21. (Scale bar: 50 um.) …”
  5. 5
  6. 6

    The 5’SS motif decreases mRNA stability and promotes nuclear retention. by Eliza S. Lee (715538)

    Published 2015
    “…Note that the relative level of <i>c-ftz-Δi-V5-His</i> decreases over the first 60 min until 40–50% of the mRNA remains, after which point the ratio is stable. …”
  7. 7
  8. 8
  9. 9

    Decreased oscillatory flow decreases <i>klf2a</i> expression. by Julien Vermot (257990)

    Published 2009
    “…The decreased heart rate and RFF is rescued by elevating the temperature to 34°C (red data point). …”
  10. 10
  11. 11

    Behavior of split<sup><50cM</sup> <i>ClvR</i> V2 with linkage. by Georg Oberhofer (3401438)

    Published 2021
    “…<p>Incorporating linkage into split <i>ClvR</i> (split<sup><50cM</sup> <i>ClvR</i> V2) results in a graded increase in drive strength, and duration of <i>Rescue</i>/Cargo/gRNAs at high frequency, as the degree of linkage increases (map distance decreases). …”
  12. 12
  13. 13
  14. 14

    Loss of C9orf72 decreases mTOR activation. by Janet Ugolino (3359054)

    Published 2016
    “…Knockdown of C9orf72 significantly decreased p-S6K1 levels compared with cells treated with control shRNA (n = 3, *<i>p</i><0.5). …”
  15. 15
  16. 16
  17. 17
  18. 18
  19. 19
  20. 20