يعرض 61 - 80 نتائج من 148,663 نتيجة بحث عن '(( 50 we decrease ) OR ( 10 ((((mean decrease) OR (teer decrease))) OR (a decrease)) ))', وقت الاستعلام: 0.86s تنقيح النتائج
  1. 61
  2. 62
  3. 63
  4. 64

    FTY720 treatment decreased tumor growth in a xenograft model of hepatoblastoma. حسب Laura L. Stafman (6577184)

    منشور في 2019
    "…<p>(A) HuH6 cells (2.5 x 10<sup>6</sup> cells in 25% Matrigel) were injected subcutaneously into the right flank of 6-week-old female athymic nude mice. …"
  5. 65
  6. 66
  7. 67

    S1 Dataset - حسب Nelmo Jordão Manjate (16324619)

    منشور في 2023
    "…For diagnosis by nasal Ag-RDTs, Panbio was MZN 547.00 (USD 8.90), COVIOS was MZN 768.00 (USD 12.50), and LumiraDx was MZN 798.00 (USD 13.00). Medical supplies expenditures represented the main driver of the final cost (>50%), followed by personnel and overhead costs (mean 15% for each). …"
  8. 68
  9. 69
  10. 70
  11. 71

    DataSheet_1_Decrease in Serum Urate Level Is Associated With Loss of Visceral Fat in Male Gout Patients.docx حسب Zijing Ran (11429935)

    منشور في 2021
    "…Objective<p>To clarify the relationship between serum urate (SU) decrease and visceral fat area (VFA) reduction in patients with gout.…"
  12. 72
  13. 73
  14. 74

    NEMA IEC body phantom. حسب Masakazu Tsujimoto (22339504)

    منشور في 2025
    الموضوعات:
  15. 75
  16. 76
  17. 77
  18. 78
  19. 79

    Repetitive stress induces a decrease in sound-evoked activity. حسب Ghattas Bisharat (20706928)

    منشور في 2025
    "…(d) Noise-evoked activity rates at different noise intensities for chronically tracked PV cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 31 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 49.6, <i>p</i> = 2.6 × 10<sup>−12</sup>, condition: intensity interaction F = 1.94, <i>p</i> = 0.02, nested ANOVA (mouse nested within session), F = 56.5, <i>p</i> = 8.8 × 10<sup>−14</sup>, condition: intensity interaction F = 3.5, <i>p</i> = 3.5 × 10<sup>−05</sup>). …"
  20. 80