بدائل البحث:
large decrease » larger decrease (توسيع البحث), marked decrease (توسيع البحث), large increases (توسيع البحث)
teer decrease » greater decrease (توسيع البحث)
_ decrease » _ decreased (توسيع البحث), _ decreasing (توسيع البحث)
a mean » _ mean (توسيع البحث)
large decrease » larger decrease (توسيع البحث), marked decrease (توسيع البحث), large increases (توسيع البحث)
teer decrease » greater decrease (توسيع البحث)
_ decrease » _ decreased (توسيع البحث), _ decreasing (توسيع البحث)
a mean » _ mean (توسيع البحث)
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Dox-inducible expression of HA-MAD1 in colon is sufficient to decrease p53 expression and cause chromosome missegregation.
منشور في 2024"…Colors indicate samples from different animals. Large circles show mean of cells from 5 fields of view from a single animal. …"
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ECoG timescales decrease during spatial attention.
منشور في 2025"…Bottom: timescales significantly decrease during covert attention relative to the attend-out condition (two locations: <i>p</i> = 0.0244; four locations: <i>p</i> < 0.0001; mean ± SEM; whiskers indicate maximum and minimum; dots correspond to individual electrodes). …"
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Image 6_Exploration of the diagnostic and prognostic roles of decreased autoantibodies in lung cancer.tif
منشور في 2025"…Almost all the TAAbs applied for diagnosis are those elevated, however, there are still large numbers of autoantibodies detected to decrease in tumor serums, and their functions were rarely known. …"
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Repetitive stress induces a decrease in sound-evoked activity.
منشور في 2025"…(d) Noise-evoked activity rates at different noise intensities for chronically tracked PV cells in baseline and repeated stress conditions (<i>N</i> = 5 mice, <i>n</i> = 31 neurons, mean ± SE). Activity rates decreased during repeated stress compared to baseline (2-way ANOVA, condition F = 49.6, <i>p</i> = 2.6 × 10<sup>−12</sup>, condition: intensity interaction F = 1.94, <i>p</i> = 0.02, nested ANOVA (mouse nested within session), F = 56.5, <i>p</i> = 8.8 × 10<sup>−14</sup>, condition: intensity interaction F = 3.5, <i>p</i> = 3.5 × 10<sup>−05</sup>). …"