يعرض 1 - 18 نتائج من 18 نتيجة بحث عن '(( ct values increased ) OR ( a marked decrease ))~', وقت الاستعلام: 0.36s تنقيح النتائج
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    <b>The Influence of Pre-Exposure to Marine Heatwaves on the Critical Thermal Maxima (CT</b><sub><strong>max</strong></sub><b>) of Marine Foundation Species</b> حسب Nathan King (8559951)

    منشور في 2024
    "…CT<sub>max</sub> is increasingly used to assess MHW population vulnerability but studies estimating CT<sub>max</sub> across species, range-edges, and thermal histories in a comparable manner remain lacking. …"
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    Loss of Lsd1 in long bone mesenchymal cells leads to impaired ossification and growth. حسب Petri Rummukainen (4247122)

    منشور في 2022
    "…A-E: n = 5-7/group, F: n = 5/group. P-values for statistically significant differences are marked * P<0.05, ** P<0.01, *** P<0.001.…"
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    Impact of pathogen shedding characteristics on estimation accuracy. حسب Yun Lin (77976)

    منشور في 2025
    "…The violin plot represents the distribution of the detected Ct values for the 200 randomly selected individuals in each trajectory panel, and the horizontal dashed line represents the median Ct value at detection for individuals infected with each pathogen during the increasing epidemic as a reference for comparing the Ct distributions for each pathogen during different epidemic periods. …"
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    Data_Sheet_1_Prognostic Impact of Left Ventricular Ejection Fraction in Patients With Moderate Aortic Regurgitation: Potential Implications for Treatment Decision-Making.pdf حسب Qinghao Zhao (11182500)

    منشور في 2022
    "…In the penalized splines, the relative hazard of death or HHF monotonically increased with decreasing LVEF. In the multivariate analysis, LVEF ≤55% was identified as the best threshold for independently predicting death or HHF under medical treatment (adjusted hazard ratio [HR]: 2.18; 95% confidence interval [CI] 1.38–3.42; P = 0.001), with substantial incremental values (integrated discrimination improvement index = 0.018, P = 0.030; net reclassification improvement index = 0.225, P = 0.006; likelihood ratio test P < 0.001). …"