Showing 201 - 220 results of 1,768 for search '(( i x decrease ) OR ( 10 ((peter decrease) OR (((a decrease) OR (mean decrease)))) ))*', query time: 0.22s Refine Results
  1. 201
  2. 202

    EFFECT OF PHENOL AS A CONTAMINANT ON THE WILD PEARL OYSTER PINCTADA IMBRICATA RADIATA IN QATAR: ECOTOXICOLOGICAL APPROACH AND USE OF OYSTER SHELL STRUCTURE AS A POTENTIAL MITIGATIO... by BARAH, FARAHNAZ GHOLAMREZA

    Published 2022
    “…The highest phenol removal of real olive wastewater was at pH 10 and room temperature by OSNP-S (56.78%). Based on the adsorption isotherm model, the adsorption capacity decreased by temperature and the coefficient of determination R2 of the Freundlich adsorption isotherm model showed the best equilibrium data for phenol adsorption with the physical interaction adsorption process. …”
    Get full text
  3. 203
  4. 204
  5. 205
  6. 206
  7. 207
  8. 208
  9. 209
  10. 210
  11. 211
  12. 212
  13. 213
  14. 214
  15. 215

    Textile-Reinforced Mortar (TRM) System as a Strengthening Technique on Reinforced Concrete Beams by Afzal, Muhammad Shekaib

    Published 2016
    “…The cement-based mortar used in TRM acts as a barrier against chloride ions penetration thus protecting the main reinforcing bars from corrosion attack. …”
    Get full text
    Get full text
  16. 216
  17. 217
  18. 218
  19. 219

    Mechanical Behavior of a Novel Nanocomposite Polysulphone - Carbon Nanotubes Membrane for Water Treatment by Wang, Kui

    Published 2016
    “…The commercial CNTs had a lengths of 1 ?m to 10 ?m and outer diameters of 10 nm to 20 nm (corresponded aspect ratios ranging from 50 to 1000), with purity >95% and BET surface area of 156 m2/g. …”
    Get full text
    Get full text
  20. 220

    Fruit and vegetable consumption and cardiovascular diseases among jordanians: A case-control study by Tayyem, F. Reema

    Published 2020
    “…Results: The findings of the present study revealed that a total consumption of 3 servings of vegetable per day decreased significantly the risk of CVD to about 54% (OR = 0.46, 95% CI: 0.22-0.97, p = 0.033). …”
    Get full text
    Get full text