يعرض 341 - 360 نتائج من 13,269 نتيجة بحث عن '(( significant ((shape decrease) OR (linear decrease)) ) OR ( significantly increased decrease ))', وقت الاستعلام: 0.55s تنقيح النتائج
  1. 341
  2. 342
  3. 343
  4. 344
  5. 345
  6. 346
  7. 347
  8. 348

    Raw dataset Fig. 6. حسب Hong Zhang (25820)

    منشور في 2025
    الموضوعات:
  9. 349
  10. 350
  11. 351
  12. 352

    Fig 5 - حسب Torsten Schober (20485754)

    منشور في 2024
  13. 353

    Fig 4 - حسب Torsten Schober (20485754)

    منشور في 2024
  14. 354

    Fig 6 - حسب Torsten Schober (20485754)

    منشور في 2024
  15. 355

    Fig 9 - حسب Torsten Schober (20485754)

    منشور في 2024
  16. 356

    Fig 8 - حسب Torsten Schober (20485754)

    منشور في 2024
  17. 357

    Design of the D-trial. حسب Torsten Schober (20485754)

    منشور في 2024
    "…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
  18. 358

    Estimated mean values for light interception. حسب Torsten Schober (20485754)

    منشور في 2024
    "…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
  19. 359

    Raw data V-trial. حسب Torsten Schober (20485754)

    منشور في 2024
    "…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
  20. 360

    Raw data D-trial. حسب Torsten Schober (20485754)

    منشور في 2024
    "…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"