Showing 161 - 180 results of 39,326 for search '(( significant decrease n ) OR ( significantly related decrease ))', query time: 0.99s Refine Results
  1. 161

    Elevated IDO activity in HD mouse brains is decreased by <i>ex-vivo</i> iron chelation. by David W. Donley (3111198)

    Published 2021
    “…</b> Striatal IDO activity is increased in N171-82Q HD mice and significantly decreased by <i>ex vivo</i> iron (III) chelation (50 μM deferoxamine). …”
  2. 162

    Decreased BMP activity in MZ<i>nanog</i> is rescued by knocking down of <i>ctnnb2</i>. by Mudan He (7017239)

    Published 2020
    “…Error bars, mean ± SD, **<i>P</i> < 0.01; NS means no significant difference. (B) Relative mRNA level of <i>admp</i> was significantly decreased in MZ<i>nanog</i> at 6 hpf, and <i>radar</i> was significantly up-regulated at 2 hpf by RT-qPCR analysis. …”
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    Bar charts showing the numbers of significantly differentially expressed genes for the different contrasts. by Gillian P. McHugo (8965919)

    Published 2025
    “…The direct (DIRE) contrasts identify changes in expression in the N’Dama samples relative to the Boran samples (DIRE<sub><i>i</i></sub> = N<sub><i>i</i></sub> – B<sub><i>i</i></sub>, where N represents the N’Dama population and B represents the Boran population), the N’Dama (NDAM) and Boran (BORA) contrasts identify changes in expression within the populations relative to time 0 (NDAM<sub><i>i</i></sub> = N<sub><i>i</i></sub> – N<sub>0</sub>; BORA<sub><i>i</i></sub> = B<sub><i>i</i></sub> – B<sub>0</sub>), and the response (RESP) contrasts identify changes in expression over time in the N’Dama samples relative to the Boran (RESP<sub><i>i</i></sub> = [N<sub><i>i</i></sub> – N<sub>0</sub>] – [B<sub><i>i</i></sub> – B<sub>0</sub>]). …”
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    Decreased NO concentrations and impairment of eNOS localization in EHD2 del/del mesenteric arteries. by Claudia Matthaeus (7485782)

    Published 2019
    “…(B) DAF staining intensity is significantly reduced for EHD2 del/del arteries compared to EHD2 del/+ (L-NAME: n(del/+) = 51/3; n(del/del) = 43/3; untreated: n(del/+) = 121/3; n(del/del) = 127/3). …”
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