بدائل البحث:
significantly altered » significantly affected (توسيع البحث), significantly elevated (توسيع البحث), significantly lower (توسيع البحث)
altered decrease » altered release (توسيع البحث), observed decrease (توسيع البحث), teer decrease (توسيع البحث)
linear decrease » linear increase (توسيع البحث)
lower decrease » larger decrease (توسيع البحث), teer decrease (توسيع البحث), we decrease (توسيع البحث)
significantly altered » significantly affected (توسيع البحث), significantly elevated (توسيع البحث), significantly lower (توسيع البحث)
altered decrease » altered release (توسيع البحث), observed decrease (توسيع البحث), teer decrease (توسيع البحث)
linear decrease » linear increase (توسيع البحث)
lower decrease » larger decrease (توسيع البحث), teer decrease (توسيع البحث), we decrease (توسيع البحث)
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Increased or reduced ATGL-1 activity does not significantly change <i>N. parisii</i> growth.
منشور في 2025الموضوعات: -
124
Design of the D-trial.
منشور في 2024"…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
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125
Estimated mean values for light interception.
منشور في 2024"…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
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126
Raw data V-trial.
منشور في 2024"…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
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127
Raw data D-trial.
منشور في 2024"…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …"
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