Search alternatives:
significantly linear » significant linear (Expand Search), significantly lower (Expand Search), significantly longer (Expand Search)
linear decrease » linear increase (Expand Search)
teer decrease » mean decrease (Expand Search), greater decrease (Expand Search)
nn decrease » _ decrease (Expand Search), a decrease (Expand Search), mean decrease (Expand Search)
significantly linear » significant linear (Expand Search), significantly lower (Expand Search), significantly longer (Expand Search)
linear decrease » linear increase (Expand Search)
teer decrease » mean decrease (Expand Search), greater decrease (Expand Search)
nn decrease » _ decrease (Expand Search), a decrease (Expand Search), mean decrease (Expand Search)
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Antihypertensive treatment of 151 T2DM patients with hypertension at different subgroups.
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Survey-weighted association of flavonoids and six subclasses intake with MASLD.
Published 2025Subjects: -
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Design of the D-trial.
Published 2024“…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …”
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Estimated mean values for light interception.
Published 2024“…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …”
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Raw data V-trial.
Published 2024“…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …”
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Raw data D-trial.
Published 2024“…An increase in PD led to a linear decrease in inflorescence yield per plant (<i>p</i> = 0.02), whereas a positive linear relationship was found for inflorescence yield (<i>p</i> = 0.0001) and CBD yield (<i>p</i> = 0.0002) per m<sup>2</sup>. …”
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